# | Problem | Pass Rate (passed user / total user) |
---|---|---|
10966 | Infix to syntax tree |
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13456 | Walk on the tree"S" |
|
Description
Given an infix Boolean expression with parentheses, which has at most 4 variables ‘A’, ’B’, ‘C’, and ‘D’, and two operators ‘&’ and ‘|’. Build a corresponding syntax tree for it.
To parse the infix expression with parentheses, use the grammar below.
EXPR = FACTOR | EXPR OP FACTOR
FACTOR = ID | (EXPR)
EXPR is the expression, ID is one of ‘A’, ‘B’, ’C’, or ‘D’, and OP is one of ‘&’ or ‘|’.
You will be provided with main.c and function.h. main.c contains the implementation of functions printPrefix and freeTree. function.h contains the definition of tree node and variables. You only need to implement the following three functions in function.c.
BTNode* makeNode(char c) // create a node without any child
BTNode* EXPR() // parse an infix expression and generate a syntax tree
BTNode* FACTOR() // use the parse grammar FACTOR = ID | (EXPR) to deal with parentheses
For OJ submission:
Step 1. Submit only your function.c into the submission block.(Please choose C compiler)
Step 2. Check the results and debug your program if necessary.
Input
The input contains N infix expressions, which has at most 4 variables ‘A’, ’B’, ‘C’, and ‘D’, two operators ‘&’ and ‘|’, and parentheses. All parentheses are matched.
Output
The output contains N prefix expressions without parentheses, which are preorders of syntax trees.
Sample Input Download
Sample Output Download
Partial Judge Code
10966.cPartial Judge Header
10966.hTags
Discuss
Description
You are given some binary trees of total N vertices numbered from 1 to N.
And M branches connect those trees.
There are Q questions.
Print every direction if you want to walk from node A to node B (Guaranteed only one path if it can be reached),
or "oops" if you can't walk there.
P: move to parent
R: move to right child
L: move to left child
B: move to branch
Limit:
Testcases 1~2: only one tree, M = 0.
Testcase 3: no more than two trees.
Testcases 4~5: N, M <= 3000.
Input
The first line contains two integers N, M (2≤N, M≤3000).
Each of the next N lines contains 2 integers, representing the left child and the right child of the i th node. (and 0 means empty)
Each of the next M lines contains 2 intergers Bi, Bj, representing there is a branch between the Bi node and the Bj node.
The next line contains an integer Q (1≤Q≤3000).
Each of the next Q lines contains two integers, A, B.
Output
For each question, output every direction that walks from node A to node B, or "oops" if you can't walk there.
Remember to add a new line in the end of each question.