| # | Problem | Pass Rate (passed user / total user) |
|---|---|---|
| 10066 | I2P homework2a |
|
| 11113 | Thousands Separator Lite |
|
Description
The input is a three-digit integer N that consists of digits 1-9 except 0. For example, 489 is such a number. The task is to reverse the order of the digits of N to get a new three-digit number M, and compute the average of the N and M. For example, if N is 489, then M is 984, and the answer should be 736.5.
Input
A three-digit integer consisting of 1-9 except 0
Output
The average of the input number and its reversal
The answer should be expressed as a floating point number with precision to the first decimal place. For example, 333.0 or 736.5
Note that you do not need to print ‘\n’ at the end of the output.
Sample Input Download
Sample Output Download
Tags
Discuss
Description
To represent a decimal number clearly and formally, one must insert commas (,) for the thousands separators, and a period (.) to separate the integer part from the fractional part.
For example, the number "123456789.012" should be represented as "123,456,789.012".
Now you have 2 such numbers in the standard format, and you want to calculate the summation of them.
Input
There are 2 lines in each case, and each line contains a number T in the standard format, where 1,000,000 ≤ T ≤ 499,999,999 and NO fractional part.
Output
For each case, you should output one line that exactly contains the summation of the 2 numbers, which is a integer without any commas.